AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

A body is projected horizontally from the top of a tall tower with a velocity of 30 ms ‌–1 . At time t1, its horizontal and verticalcomponents of the velocity are equal and at t2 , its horizontal and vertical displacements are equal. Then (t2−t1)=
(g = 10 ms ‌–2 )