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Question : 76 of 160
Marks:
+1,
-0
Solution:
Consider the expression,
{sin5()+sin5() +sin5()+.....+sin5()}Simplify the above,
{sin5()+sin5() +sin5()+.....+sin5()}= ‌sin5()=sin5(x)dxLet,
x=tThen for upper limit,
x=3,t=And for lower limit
x=0,t=0 and
dx=dtSo,
sin5(x)dt=‌sin5(t)dt=()=
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