A random variable X has the following distribution Values of X (x) 0 1 2 3 4 5 6 7 P(X=x) 0 k 2k 2k 3k k ^2 2k^2 7k^2+k Then P (0

AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

Section: Mathematics

Question : 40 of 160

Marks: +1, -0

A random variable X has the following distribution Values of

X(x)	0	1	2	3	4	5	6	7
P(X=x)	0	k	2k	2k	3k	k2	2k2	7k2+k

Then P(0<X<6)=

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