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Question : 34 of 160
Marks:
+1,
-0
Solution:
Consider the given data,
(b×c)×(c×a)=[a b c]c(c×a)×(a×b)=[a b c]a(a×b)×(b×c)=[a b c]bAnd,
[(b+c)(c+a)(a+b]=2[a b c][(b×c)(c×a)(a×b)]=[a b c]2Then,
=
| [a b c]c[a b c]a[a b c]b |
| 2[a b c][a b c]2 |
===1
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