AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

The number of three digit numbers in which 9 appears at hundred place only is,
n=1×9×9
n=81
The number of three digits numbers in which 9 appears at ten or unit place only is,
N=(8×1×9)×2
N=144
So, the required number is,
n+N=81+144
=225