AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

Given,

→

E

=(3

^

i

+4y

^

j

)Vm−1 ...... (I)
The standard equation of electric field is,

→

E

=

−∂Vx

∂x

^

i

+

−∂Vy

∂y

^

j

...... (II)
From equation (I) and (II),

−∂Vx

∂x

=3⇒Vx=−3x

−∂Vy

∂y

=4y⇒Vy=−2y2
The potential function is,
V=−(3x+2y2)
The potential function at point (2, 1) is,
V=−(3×2+2×12)
V=−8V