Correct Answer is : y = 12[sin2x+c1−tan2x]

y = 1/2[\frac{tan2x+c}{1-\tan^2x}]

y = 1/2[\frac{cos2x+c}{1-\tan^2x}]

y = 1/2[\frac{sin2x+c}{1-\tan^2x}]

y = 1/2[\frac{sinx+c}{1-\tan^2x}]

AP EAMCET Engineering 2018 Apr 23 Shift 1 Paper

Section: Mathematics

Question : 80 of 160

Marks: +1, -0

if -

< x <

, then the general solution of the differential equation
cos2 x .

- (tan 2x) y = cos4 x is

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