∫ \frac{\cos^3 x + \cos^5 x}{\sin^2 x + \sin^4 x} dx =

Correct Answer is : sin x - 2 (sinx)−1 - 6 tan−1 (sin x) + x

sin x - 6 \tan^{-1} (sin x) + x

sin x - 2 (sinx)^{-1} - 6 \tan^{-1} (sin x) + x

sin x - 2 (sinx)^{-1} + 5 \tan^{-1} (sin x) + x

AP EAMCET Engineering 2018 Apr 23 Shift 1 Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫

cos3x+cos5x

sin2x+sin4x

dx =

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