AP EAMCET Engineering 2018 Apr 23 Shift 1 Paper

Section: Mathematics

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Question : 22 of 160

Marks: +1, -0

If A = {x ∊ [0 , 2π] / tan x - tan2 x > 0} and B = {x ∊ [0 , 2π] / |sin x| <

1

2

} , then A ∩ B =

(0,
π
6
) ∪ (π,
7π
6
)
(0,
π
4
) ∪ (π,
7π
6
)
(0,
π
6
) ∪ (
5π
6
,
7π
6
)
(
π
6
,
7π
6
)

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