AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper

The following figure represents the required diagram. With

1

n

th part of hanging the potential energy of chain is given by,
P

1

n

‌th=−

Mgl

2n2

When the chain leaves table, the potential energy of chain is given by,
PL=−

Mgl

2

From the conservation of energy,
Kinetic energy = Loss in potential energy

1

2

Mv2=

Mgl

2

(1−

1

n2

)
v=√gl(1−

1

n2

)