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Question : 67 of 160
Marks:
+1,
-0
Solution:
From the equation,
y=sin(log(x2+2x+1))=sin[2‌log(x+1)]Differentiate with respect to x .
=[cos(2‌log(x+1))]×() (x+1)=2‌cos(2(log(x+1)))Differentiate above equation with respect to x ,
(x+1)+ =−2(sin(2‌log(1+x)))()(x+1)2+(x+1)=−4y
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