AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper

The point of intersection of line L = 0 and line segment PQ is,
=R(

6

5

,

3

5

)
For point R on line L = 0 is,

18

5

+

12

5

−k=0
k=6
Now, equation of line concurrent with the lines L = 0 and PQ,
(3x+4y−6)+λ(2x+y−3)=0
The above line is parallel to x = y , so
−

3+2λ

4+λ

=1
λ=−

7

3

So, the equation of the line is,
5x−5y−3=0