AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper

Section: Mathematics

© examsiri.com

Question : 42 of 160

Marks: +1, -0

The equation of the locus of a point (2‌cos‌θ−3,3‌sin‌θ−4) is

9x2+4y21+54x+32y +181=0
4x2+9y2+54x+32y +109=0
9x2+4y2−54x+32y +109=0
9x2+4y2+54x+32y +109=0

Go to Question:

Prev Question

Next Question