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Question : 34 of 160
Marks:
+1,
-0
Solution:
Solve the expression,
(α×(β+γ))×(β×γ).(β−γ)
=(α×(β+γ)).[(β×γ)×(β−γ)]
=(α×(β+γ)).[|β|2−β.γ)γ −(γ.β−|γ|2)β]
=(1−β.γ)[(α×β).γ+(α×γ).β]
=(1−β.γ)[(α×β).γ−(α×β).γ]
= 0
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