AP EAMCET Engineering 2018 Apr 22 Shift 2 Paper

The below figure represent the required circuit diagram.Given information,
The Emf of each cell is equal to 2.16 V and the Emf of circuit is equal to 4.32 V.
The current in circuit is calculated by using,
I=

4.32

r1+r2+19.6

Use V = E – Ir for each cell.
For P,
2=2.16−

4.32r1

r1+r2+19.6

4.32r1

r1+r2+19.6

=0.16 ...... (1)
For Q,
1.92=2.16−

4.32r2

r1+r2+19.6

4.32r1

r1+r2+19.6

=0.24 ....... (2)
From Equation (1) and (2) we get,
r1:r2=2:3