The derivative of f (x) = x^{\tan^{-1}} with respect to g (x) = \sec^{-1}(1/{2x^2-1}) is

Correct Answer is : −12√1−x2 xtan−1x [logx1+x2+tan−1xx]

1/2\sqrt{1-x^2} x^{\tan^{-1}x} [\frac{logx}{1+x^2}+{\tan^{-1}x}/x]

- 1/2\sqrt{1-x^2} x^{\tan^{-1}x} [log (\tan^{-1}x) + x (1 + x^2) \tan^{-1}x]

{-2tan^{-1}x[\frac{logx}{1+x^2}+{\tan^{-1}x}/x]}/\sqrt{1-x^2}

- 1/2\sqrt{1-x^2} x^{\tan^{-1}x} [\frac{logx}{1+x^2}+{\tan^{-1}x}/x]

AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

Section: Mathematics

Question : 65 of 160

Marks: +1, -0

The derivative of f (x) = xtan−1 with respect to g (x) = sec−1(

2x2−1

) is

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