AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

The equation of sides of parallelogram is given as,
ax2+2hxy+by2=0
The equation of diagonal of parallelogram is given as.
lx+my=1
The other diagonal is given as.
y(bl−hm)=x(am−hl) ......(I)
Here, a=2,b=2,h=

3

2

l=−3,m=−1
On substitution of value in equation ( I ) we get,
y(6+

3

2

)=x(−2+

9

2

)
y (

15

2

)=x(

5

2

)
3y=x
x−3y=0