AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

The equation of the line is taken as.

x

a

+

y

b

=1
The coordinate axes at line meets is A(a,0) and B(0,b) respectively and its ratio is given as 3:(2)
(

3×0+2×a

3+2

,

3×b+2×0

3+2

) =(

2a

5

,

3b

5

)
Now.According to give condition at point (2,-1)
(

2a

5

,

3b

5

)=(2,−1)

2a

5

=2,

3b

5

=−1
a=5,b=−

5

3

The required equation of line become.

x

5

+

y

(− 5 3 )

=1
x−3y=5
x−3y−5=0