AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

A point P is taken with coordinates of (x,y), the according to condition.
PA2+PB2=2PC2
(x−2)2+(y−3)2+(x−3)2+(y+6)2=
2[(x−5)2+(y+7)2]
On solving the above expression we get,
10x−22y=90
By going though options, the points became (-13,-10) which lies on the locus of P.