AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

The total possible outcome is.
n=63=216
Here, we choose any 3 numbers out of 6 numbers and place them in ascending order in only one way.
The favorable outcome is,
nf=6C3=20
The required probability is,
P=

nf

n

=

20

216

=

5

54