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Question : 31 of 160
Marks:
+1,
-0
Solution:
It is given,
vec‌a=−2−3 b=2+− c=+3−2 Now,
(a×b)×(b×c)=[a b c]b (b×c)×(c×a)=[a b c]c (c×a)×(a×b)=[a b c]a ∴[(a×b)×(b×c)(b×c)×(c×a)(c ×a)×(a×b)] =[−20b−20c−20a] =|| −40 | −20 | 20 |
| −20 | −60 | 40 |
| −20 | 40 | 60 |
| =−40(−3600−1600)+20(−1200+800) +20(−2000) =160000
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