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AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper
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Section:
Mathematics
© examsiri.com
Question :
22 of 160
Marks:
+1
,
-0
cos
3
110
°
cos
3
10
°
cos
3
130
°
=
3
4
3
8
3
√
3
8
3
√
3
4
Validate
Solution:
It is given that,
cos
3
10
°
+
cos
3
110
°
+
cos
3
130
°
We know,
cos
3
x
+
cos
3
(
120
−
x
)
+
cos
3
(
120
+
x
)
=
3
4
‌
cos
‌
3
‌
x
In this case
x
is taken as 10 .
cos
3
10
°
+
cos
3
110
°
+
cos
3
130
°
=
cos
3
10
°
+
cos
3
(
120
°
−
10
°
)
+
cos
3
(
120
°
+
10
°
)
cos
3
10
°
+
cos
3
110
°
+
cos
3
130
°
=
(
3
4
)
‌
cos
(
3
×
10
°
)
=
3
4
‌
cos
‌
30
°
=
3
√
3
8
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