AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

It is given.

x2+5x+7

(x−3)3

=

A

x−3

+

B

(x−3)2

+

C

(x−3)3

x2+5x+7=A(x−3)2 +B(x−3)+C ......(I)
Substituting the value of x as 3 in above equation we get.
C=9+15+7=31
Substituting the value of x as 0 in above equation we get,
9A−3B+31=7
3A−B=−8
Substituting the value of x as 1 in above equation we get,
4A−2B+31=1+5+7
2A−B=−9
Pn solving the above two to obtain the value of A and B.
A=1 and B=11
The equation of line having slope A and passing through the point (B,C) is,
y−31=1(x−11)
y−31=x−11
x−y+20=0