AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

The figure below shows the direction of magnetic field.The magnetic field at an axial point is,
B1=

µ0

4π

×

2M

r3

=10−7×

2×9

27×10−6

B1=

2

3

×10−1T
The magnetic field at an equatorial point is,
B2=

µ0

4π

×

M

r3

=10−7×

9

27×10−6

B2=

1

3

×10−1T
The net effective magnetic field is,
B=B1+B2
Substitute the value in above expression.
B=(

2

3

×10−1+

1

3

×10−1)T
B=0.1T