AP EAMCET Engineering 2018 Apr 22 Shift 1 Paper

The figure below shows the state at which car is at rest,The tension in this case is.
T=Mg=mv12
v1=√

T

m

=√

Mg

m

Substitute the value in above expression.
60=√

T

m

=√

Mg

m

The figure below shows when there is some acceleration in car.
T2=√(Ma)2+(Mg)2=mv22
v2=

[(Ma)2+(Mg)2]1∕4

m1∕2

Substitute the value in above expression.
66=

[(Ma)2+(Mg)2]1∕4

m1∕2

On dividing both we get.

(a2+g2) 1 2

g

=

121

100

a2+g2=(

121

100

)2
a2=146.41−100
a=6.8m∕s2