The probability distribution of a random variable is given below X=x 0 1 2 3 4 5 6 7 P(X=x) 0 K 2K 2K 3K K^2 2K^2 7K^2+K Then P (0

AP EAMCET Engineering 2015 Code C Paper

Section: Mathematics

Question : 6 of 160

Marks: +1, -0

The probability distribution of a random variable is given below

X=x	0	1	2	3	4	5	6	7
P(X=x)	0	K	2K	2K	3K	K2	2K2	7K2+K

Then P(0<X<5)=

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