Let Q be the set of all rational numbers in [0,1] and f:[0,1]\to[0,1] be defined by f(x)=\\begin{array}{ccc}x & for & x∊Q\\1-x & for & x\notinQ^{•\end{array} Then the set S=\{x∊[0,1](fof)(x)=x\} is equal to

AP EAMCET Engineering 2014 Code A Solved Paper

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Let Q be the set of all rational numbers in [0,1] and f:[0,1]→[0,1] be defined by f(x)={

x	for	x∊Q
1−x	for	x∉Q•

Then the set S={x∊[0,1](fof)(x)=x} is equal to

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