AP EAMCET Engineering 2013 Solved Paper

KE=

3

2

RT for 1 mole of the gas.
∵4g of H2 gas has 2 moles of H2
∴ It has 2 times KE as compared to 1 mole of gas
But 8g of O2 gas has 1∕4 moles of O2;
∴ It has one fourth part of the KE as compared to 1 mole of gas.
Hence, ratio of KE of H2 and O2
KEH2:KEO2=2:

1

4

=8:1