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Question : 153 of 160
Marks:
+1,
-0
Solution:
Let
I=∫ex(| 2+sin‌2‌x |
| 1+cos‌2‌x |
)dx =∫ex{+}dx =∫ex{+| 2‌sin‌x‌cos‌x |
| 2cos2x |
}dx =∫ex(sec2x+tan‌x)dx =∫exsec2xdx+∫ex‌tan‌x‌d‌x =ex‌tan‌x−∫ex‌tan‌x‌d‌x+∫ex‌tan‌x‌d‌x =ex‌tan‌x+C
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