AP EAMCET Engineering 2013 Solved Paper

Given points (1,π),(1,0°) and (1,

π

2

) are in polar form.
Now, change in cartesian form,
(1,π)→(1.cos‌π,1.sin‌π)→(−1,0)
(1,0°)→(1.cos‌0°,1.sin‌0°)→(1,0)
and (1,

π

2

)→(1.cos‌

π

2

,1.sin‌

π

2

) →(0,1)
Now, equation of the line passing through (1,0) and (0,1) is
(y−0)=

1−0

0−1

(x−1)
⇒ y=−x+1
⇒ x+y−1=0 ......(i)
So, the perpendicular distance from the point (−1,0) to the line (i) is
=

|−1+0−1|

√1+1

=

2

√2

=√2