AP EAMCET Engineering 2013 Solved Paper

Let m1 and m2 be the slopes of lines.
Then, m1+m2= arithmetic mean =

13

2

.....(i)
and m1m2= geometric mean =√36=6 .....(ii)
Now, equation of the pair of lines passing through the origin is
(y−m1x)(y−m2x)=0
⇒y2−(m1+m2)xy+m1m2x2=0
Using Eq. (i) and (ii), we get
y2−

13

2

xy+6x2=0
⇒ 12x2−13xy+2y2=0