AP EAMCET Engineering 2013 Solved Paper

Let I1≡2x+3y=5 .....(i)
Since, line AB⊥l1
∴ Slope of I1 is
m1 say =

−2

3

∴ Slope of AB=

−1

(−2∕3)

=

3

2

Equation of line AB is
(y−

1

3

)=

3

2

(x−1)
⇒ 3x−2y=

7

3

......(i)
Equation of line I1 is
2x+3y=5 .....(ii)
From Eqs. (i) and (ii), we get
13x=17
⇒ x=

17

13

From Eq. (i), we get
3y=5−

34

13

⇒y=

65−34

13×3

=

31

39

So, mid-point P→(

17

13

,

31

39

)
Coordinate of point B
=(

17

13

×2−1,

31

39

×2−

1

3

)
=(

34−13

13

,

62−13

39

)=(

21

13

,

49

39

)