AP EAMCET Engineering 2012 Solved Paper

The molecular orbital electronic configuration of O2 is
O2(8+8=16e−)=σ1s2,

*

σ

1s2,σ2s2,

*

σ

2s2,
σ2pz2,π2px2≈π2py2,

*

π

2px1≈

*

π

2py1
(Unstarred σ and π represent bonding orbitals.)
∴ number of bonding electrons =10
and number of bonding electron pairs =5