Drops of liquid of density d are floating half immersed in a liquid of density \\rho . If the surface tension of the liquid is T, then the radius of the drop is

Correct Answer is : √3Tg(2d−ρ)

\\sqrt{\frac{3 T}{g(3 d-\\rho )}}

\\sqrt{\frac{6 T}{g(2 d-\\rho )}}

\\sqrt{\frac{3 T}{g(2 d-\\rho )}}

\\sqrt{\frac{3 T}{g(4 d-3 \\rho )}}

AP EAMCET Engineering 2012 Solved Paper

Section: Physics

Question : 24 of 160

Marks: +1, -0

Drops of liquid of density d are floating half immersed in a liquid of density ρ. If the surface tension of the liquid is T, then the radius of the drop is

√
3T
g(3d−ρ)
√
6T
g(2d−ρ)
√
3T
g(2d−ρ)
√
3T
g(4d−3ρ)

Validate

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