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Question : 132 of 160
Marks:
+1,
-0
Solution:
Given,
A=[] and
B=[] ∴A2=[][] =[| i2+i2 | −i2−i2 |
| −i2−i2 | i2+i2 |
] =[] =[]=−2B B2=[][] =[] =[] =2B ......(i)
Now,
A8=(A2)4=(−2B)4 =16B4=16(B2)216.(2B)2 =16×4×B2=16×4×2B[ from Eq. (i)
] =128B
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