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Question : 124 of 160
Marks:
+1,
-0
Solution:
Given equation is
(tan−1x)2+(cot−1x)2= (tan−1x+cot−1x)2−2tan−1x. cot−1x= [∵tan−1x+cot−1x=] ⇒
−2tan−1x(π∕2−tan−1x) = ⇒
−2.+2(tan−1x)2 =− ⇒
(tan−1x)2−= ∴
tan−1x= ⇒
tan−1x= =,− ⇒
x=tan(),tan(−) ⇒
x=−1,−1
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