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Question : 115 of 160
Marks:
+1,
-0
Solution:
Given,
A=[] ∴A2−2A=[] −[] =[] ......(i)
Now,
|A|=1(0−1)−0+1(0)=−1 C11=−1,C12=0,C13=0 C21=−(−1)=1,C22=0,C23=−1 C31=−1,C32=−(1),C33=1 ∴
A−1=−1[] ∴ From Eq. (i)
A2−2A=−A−1
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