AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

The temperature at point A is
TA=‌

3p0V0

R

The temperature at point B is
TB=‌

30p0V0

R

The expression of the change in internal energy due to adiabatic process is,
∆U=nCv∆T
∆U=‌

3

2

R∆T
The expression of the work done in process A to B is,
W=18p0V0
W=‌

2

3

R∆T
From 1‌st ‌ law of thermodynamics for process A to B
Q=∆U+W
nC∆T‌‌=‌

3

2

R∆T+‌

2

3

R∆T
(1)C∆T‌‌=‌

3

2

R∆T+‌

2

3

R∆T
C‌‌=‌

13

6

R