AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

Section: Mathematics

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Question : 76 of 160

Marks: +1, -0

lim

n→∞

[

1

n

+

n2

(n+1)2

+

n2

(n+2)3

+

n2

(n+3)3

+...+

1

125n

]

=

3
8
15
32
12
25
35
72

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