If x = sec θ - cos θ , y = \sec^{10} \theta - \cos^{10} \theta and (x^2+4)(\frac{dy}{dx})^2 = k (y^2+4) , then k =

AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

Section: Mathematics

Question : 66 of 160

Marks: +1, -0

If x = sec θ - cos θ , y = sec10θ−cos10θ and (x2+4)(

)2 = k (y2+4) , then k =

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