AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

Consider the equation of curve,
x2+xy+y2+x+3y+1=0
The equation of line joining the origin to the point of intersection of curve and the line is calculated as,
x2+xy+y2+(x+3y)(

x+y

−2

)+(

x+y

−2

)2=0
x2+y2+xy−

1

2

(x2+4xy+3y2)+

1

4

(x2+2xy+y2)=0
3x2−2xy−y2=0
The equation of the bisector of the angle between the pair of straight line is,

x2−y2

3+1

=

xy

−1

x2+4xy−y2=0