AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

The equation of perpendicular bisector of the line joining the points A(−2,−1) and B(6,−1) is,
x=2
The equation of perpendicular bisector of the line joining the points B(6,−1) and C(2,5) is,
y−2=‌‌

4

6

(x−4)
2x−3y=2
The point of intersection of perpendicular bisector of the circumcentre of triangle‌A‌B‌C.
C(2,‌‌

2

3

)
Thus, the required quadratic equation is,
x2−(2+‌‌

2

3

)x+2(‌‌

2

3

)=0
3x2−8x+4=0