AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

A number is divisible by 6 if it is divisible by both 2 and 3.
Thus, the last digit can be filled by 0, 2, 4 only.
The first place can be filled by 5 choices except 0 and second and third by 6 choices.
The fourth placed is filled such that it must of the form 3k or 3k + 1 or 3k + 2. Thus it can be filled by only two choices 0 or 3.
Hence the total numbers are,
Number = 5 × 6 × 6 × 2 × 3 = 1080