The bond order of N2(14) is shown below. N2:(σ1s)2,(σ*1s)2,(σ2s)2,(σ*2s)2,(π2px)2≈(π2py)2,(σ2pz)2 The Bond order can be calculated as: B⋅O=‌
10−4
2
=3 The bond order of N2+(13) is shown below. N2+:(σ1s)2,(σ*1s)2,(σ2s)2,(σ*2s)2,(π2px)2≈(π2py)2,(σ2pz)1 The Bond order can be calculated as: B⋅O=‌
9−4
2
=2.5 The bond order of O2(16) is shown below. O2:(σ1s)2,(σ*1s)2,(σ2s)2,(σ*2s)2,(σ2pz)2,(π2px)2≈(π2py)2,(π*2px)1≈(π*2py)1 The Bond order can be calculated as: B⋅O=‌
10−6
2
=2 The bond order of O2+(15) is shown below. O2+:(σ1s)2,(σ*1s)2,(σ2s)2,(σ*2s)2,(σ2pz)2,(π2px)2≈(π2py)2,(π*px)1≈(π*2py)0 The Bond order can be calculated as: B.O=‌
10−5
2
=2.5 Bond length is reverse of bond order. Therefore, In N2+, as bond order decreases, bond length increases. In O2+, as bond order increases, bond length decreases.