An electron of charge 'e' and mass 'm' moving with an initial velocity v_0i^{\^} is subjected to an electric field E_0 j^{\^} . The de-Broglie wavelength of the electron at a time 't' is (Initial de-Broglie wavelength of the electron = \lambda_0)

Correct Answer is : λ0√1+e2E02t2m2v02

\lambda_0 \sqrt{1+\frac{e^2E_0^2t^2}{m^2v_0^2}}

\lambda_0/\sqrt{1+\frac{e^2E_0^2t^2}{m^2v_0^2}}

\lambda_0/({1+\frac{e^2E_0^2t^2}{m^2v_0^2}})

AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

Section: Physics

Question : 116 of 160

Marks: +1, -0

An electron of charge 'e' and mass 'm' moving with an initial velocity v0

is subjected to an electric field E0

. The de-Broglie wavelength of the electron at a time 't' is (Initial de-Broglie wavelength of the electron = λ0)

Go to Question:

Prev Question

Next Question