AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

The expression of the electric potential difference between two point is,
∆V=−∫E⋅dr
Substitute values and integrate above equation,

∆V=−∫(x

∧

i

−2y

∧

j

+z

∧

k

)⋅(dx

∧

i

+dy

∧

j

+dz

∧

k

)

∆V=−

0

∫

2

xdx+2‌

2

∫

1

ydy−

4

∫

0

zdz

∆V=[‌

x2

2

]20+[y2]2−[‌

z2

1

]04

∆V=−3V
Thus, the magnitude of electric potential difference is,
|∆V|=3V