AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

The work done from A to B can be calculated as,
WAB‌‌=P×dV
‌‌=10×(2−1)
‌‌=10J
As the change in volume is zero during the process BC therefore, work done is zero. From first law of thermodynamics,
∆Q=∆U+W
The internal energy change in whole process comes out to be 0 . Therefore,
Q=W
Q=WAB+WBC+WCA
Substituting the values in the above equation, we get
WCA‌‌=5−WAB−WBC
‌‌=5−10−0=−5J
Thus, the magnitude of work in the process A to C is 5 J.