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Question : 9 of 160
Marks:
+1,
-0
Solution:
Consider the expression
1+ω+ω2=0 And
ω3=1 Then
(r+)(r+)=r2+r(+)+ =r2+()r+ =r2−r+1 Then
(r+)(r+)=(r2−r+1) =−+n =[2n+1−3]+n =(2n−2)+n Further simplify the above,
(r+)(r+)=(n2−1)+n =[n2−1+3] =
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