AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

The figure below shows the free body diagram.Applying the equilibrium along vertical direction,
R=(W+F‌sin‌60∘)
Applying the equilibrium along horizontal direction,
F‌cos‌60∘=µR
F‌cos‌60∘=µ(W+F‌sin‌60∘)
Substituting the values in the above expression, we get
‌

F

2

=‌

1

2√3

[10√3+F(‌

√3

2

)]
F=20N