AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

The velocity of an object is given as,
v=6t−3t2
As velocity is the rate of change of displacement therefore,
v‌‌=‌

dx

dt

dx‌‌=vdt
Integrating both sides by taking the limit from t=0 to t=2, we get
x‌‌=

2

∫

0

vdt=

2

∫

0

(6t−3t2)dt
‌‌=[3(2)2−(2)3]
‌‌=12−8=4m
The average velocity is given as,
vavg=‌

‌ Total displacement ‌

‌ Total time ‌

=‌

4

2

=2‌m∕s